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The calcium carbonate (CaCO₃) in antacid tablets reacts with dilute hydrochloric acid (HCl) according to the following balanced equation: CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l) ΔH < 0 5.1 Is the above reaction EXOTHERMIC or ENDOTHERMIC? Give a reason for the answer - NSC Physical Sciences - Question 5 - 2019 - Paper 2

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The-calcium-carbonate-(CaCO₃)-in-antacid-tablets-reacts-with-dilute-hydrochloric-acid-(HCl)-according-to-the-following-balanced-equation:--CaCO₃(s)-+-2HCl(aq)-→-CaCl₂(aq)-+-CO₂(g)-+-H₂O(l)-ΔH-<-0--5.1-Is-the-above-reaction-EXOTHERMIC-or-ENDOTHERMIC?-Give-a-reason-for-the-answer-NSC Physical Sciences-Question 5-2019-Paper 2.png

The calcium carbonate (CaCO₃) in antacid tablets reacts with dilute hydrochloric acid (HCl) according to the following balanced equation: CaCO₃(s) + 2HCl(aq) → CaCl... show full transcript

Worked Solution & Example Answer:The calcium carbonate (CaCO₃) in antacid tablets reacts with dilute hydrochloric acid (HCl) according to the following balanced equation: CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l) ΔH < 0 5.1 Is the above reaction EXOTHERMIC or ENDOTHERMIC? Give a reason for the answer - NSC Physical Sciences - Question 5 - 2019 - Paper 2

Step 1

Is the above reaction EXOTHERMIC or ENDOTHERMIC? Give a reason for the answer.

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Answer

The reaction is ENDOTHERMIC because the enthalpy change (ΔH) is less than zero (ΔH < 0). This indicates that energy is absorbed during the reaction, resulting in a decrease in temperature in the surroundings.

Step 2

Calculate the average rate (in g·s⁻¹) of the above reaction.

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Answer

To calculate the average rate of reaction, we use the formula:

extRate=ΔmΔt ext{Rate} = -\frac{\Delta m}{\Delta t}

Here, ( \Delta m ) is the change in mass of the tablet, which is ( 2 g - 0.25 g = 1.75 g ), and ( \Delta t ) is the time taken, which is 30 seconds.

Thus,

extRate=1.75g30s=0.0583gs1 ext{Rate} = -\frac{1.75 g}{30 s} = 0.0583 g\cdot s^{-1}

Therefore, the average rate of the reaction is approximately 0.058 g·s⁻¹.

Step 3

Calculate the volume of carbon dioxide, CO₂(g) that will be collected at STP.

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First, we find the moles of calcium carbonate in the antacid tablet:

Since the tablet weighs 2 g and contains 40% calcium carbonate:

m(CaCO3)=2g×0.4=0.8gm(CaCO_3) = 2 g \times 0.4 = 0.8 g

Now, convert grams to moles using the molar mass of CaCO₃ (100 g/mol):

n(CaCO3)=0.8g100g/mol=0.008moln(CaCO_3) = \frac{0.8 g}{100 g/mol} = 0.008 mol

From the balanced equation, 1 mole of CaCO₃ produces 1 mole of CO₂. Therefore, the moles of CO₂ produced:

n(CO2)=n(CaCO3)=0.008moln(CO_2) = n(CaCO_3) = 0.008 mol

At STP, 1 mole of gas occupies 22.4 L. Thus, the volume of CO₂ produced:

V(CO2)=n(CO2)×22.4L/mol=0.008mol×22.4L/mol=0.1792LV(CO_2) = n(CO_2) \times 22.4 L/mol = 0.008 mol \times 22.4 L/mol = 0.1792 L

Therefore, the volume of carbon dioxide collected at STP is approximately 0.18 L.

Step 4

Write down ONE controlled variable for this investigation.

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Answer

One controlled variable could be the concentration of the hydrochloric acid (HCl) used in the experiment.

Step 5

Write down a conclusion that can be made from the graph.

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Answer

The graph indicates that as the temperature increases, the reaction rate (1/time) also increases. This suggests a direct proportionality between temperature and reaction rate.

Step 6

Use the collision theory to fully explain the answer to QUESTION 5.5.

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Answer

According to collision theory, the rate of a chemical reaction depends on the frequency of collisions between reactant particles. As temperature increases:

  1. The average kinetic energy of the molecules increases, resulting in more frequent and energetic collisions.
  2. More molecules achieve the activation energy needed for reacting effectively.

This ultimately leads to a higher reaction rate, explaining the observed increase in rate as temperature rises.

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