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The reaction between EXCESS dilute hydrochloric acid and sodium thiosulphate is used to investigate factors that influence reaction rate - NSC Physical Sciences - Question 5 - 2023 - Paper 2

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The reaction between EXCESS dilute hydrochloric acid and sodium thiosulphate is used to investigate factors that influence reaction rate. Na₂S₂O₃(aq) + 2HCl(aq) → 2... show full transcript

Worked Solution & Example Answer:The reaction between EXCESS dilute hydrochloric acid and sodium thiosulphate is used to investigate factors that influence reaction rate - NSC Physical Sciences - Question 5 - 2023 - Paper 2

Step 1

Define reaction rate.

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Answer

The reaction rate can be defined as the change in concentration of products or reactants per unit time. It can be expressed as:

Rate = [\text{Rate} = \frac{\Delta [C]}{\Delta t}] where (\Delta [C]) is the change in concentration and (\Delta t) is the change in time.

Step 2

Write down the independent variable for this investigation.

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Answer

The independent variable for this investigation is the volume of sodium thiosulphate, Na₂S₂O₃(aq), used in each run.

Step 3

Calculate the value of P in the table.

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Answer

To find P, we need to maintain consistency in the concentration calculations. From runs 2 and 3, we can use the average concentration formula:

  1. The concentration is given by: [\text{Concentration} = \frac{\text{moles}}{\text{volume (in dm}^3\text{)}}]
  2. From Run 2: Concentration = 0.10 mol·dm⁻³ Volume = 40 cm³ or 0.04 dm³ Thus, moles of Na₂S₂O₃ = 0.10 mol·dm⁻³ × 0.04 dm³ = 0.004 moles.
  3. Run 3 has 20 cm³ = 0.02 dm³. Therefore: [ P = \frac{0.004\text{ moles}}{0.02 \text{ dm}^3} = 0.20 \text{ mol·dm}^{-3}]

Step 4

Calculate the average reaction rate with respect to sodium thiosulphate, Na₂S₂O₃(aq), in g·s⁻¹.

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Answer

Given that 0.21 g of sulphur is produced when the cross vanishes, the molar mass of Na₂S₂O₃ is needed to find the change in moles. The calculation is as follows:

  1. Molar mass of Na₂S₂O₃ is approximately 158 g/mol.
  2. Number of moles = ( n = \frac{m}{M} = \frac{0.21g}{158g/mol} \approx 0.00133 ) moles.
  3. Average reaction rate = ( \frac{0.00133\text{ moles}}{20.4 s} \approx 0.000065\text{ moles/s} \approx 0.01 ext{ g/s} ).

Step 5

Sketch the Maxwell-Boltzmann distribution curve for the reaction at 20 °C. Label this curve as A.

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Answer

When sketching the Maxwell-Boltzmann distribution, the x-axis represents kinetic energy, while the y-axis represents the number of particles. Curve A should show a peak that represents the energy distribution at 20 °C.

Curve B, which represents a higher temperature of 35 °C, will shift to the right and will have a higher peak, indicating that more particles have higher energy, which contributes to a greater frequency of effective collisions.

Step 6

Explain the effect of temperature on reaction rate in terms of the collision theory.

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Answer

As temperature increases, the kinetic energy of the particles also increases. This results in:

  1. More particles moving faster, which correlates to having higher kinetic energy.
  2. Increased frequency of collisions, as particles collide more often per unit of time.
  3. More effective collisions per unit of time, as a greater proportion of the particles possess enough energy to overcome the activation energy barrier required for the reaction. Overall, this leads to an increased reaction rate.

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