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The reaction of zinc and EXCESS dilute hydrochloric acid is used to investigate factors that affect reaction rate - NSC Physical Sciences - Question 5 - 2018 - Paper 2

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The reaction of zinc and EXCESS dilute hydrochloric acid is used to investigate factors that affect reaction rate. The balanced equation for the reaction is: $$Zn(s... show full transcript

Worked Solution & Example Answer:The reaction of zinc and EXCESS dilute hydrochloric acid is used to investigate factors that affect reaction rate - NSC Physical Sciences - Question 5 - 2018 - Paper 2

Step 1

Experiment 1 and experiment 5 are compared. Write down the independent variable.

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Answer

The independent variable is the concentration of hydrochloric acid (HCl) used in each experiment. In this case, the concentration varies between 2.0 mol·dm3^{-3} for Experiment 1 and 2.0 mol·dm3^{-3} for Experiment 5, but it is emphasized that the other factors were kept constant.

Step 2

Define reaction rate.

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Answer

Reaction rate refers to the change in concentration of reactants or products per unit time. It can be defined mathematically as:

Rate=Δ[extProducts]Δt\text{Rate} = \frac{\Delta [ ext{Products}]}{\Delta t}

This indicates how quickly reactants are converted to products over a specified time interval.

Step 3

Write down the value of k in experiment 4.

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Answer

In experiment 4, the value of k is 14 min.

Step 4

5.4.1 Experiment 3 Give a reason for the answer.

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Graph B represents Experiment 3 as it shows the highest concentration of HCl which reflects a higher number of effective collisions between reactant molecules, thereby increasing the reaction rate.

Step 5

5.4.2 Experiment 5 Give a reason for the answer.

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Graph C represents Experiment 5 as it corresponds to the highest temperature that provides sufficient kinetic energy for the reacting particles, leading to an increase in the rate of reaction.

Step 6

5.5.1 What is the function of the catalyst in this experiment?

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The catalyst speeds up the reaction by providing an alternative pathway with a lower activation energy, thus increasing the rate of reaction without being consumed in the process.

Step 7

5.5.2 How will the heat of reaction in experiment 6 compare to that in experiment 1? Choose from: GREATER THAN, EQUAL TO or LESS THAN.

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The heat of reaction in experiment 6 will be LESS THAN that in experiment 1 due to the presence of the catalyst which reduces the activation energy required for the reaction to proceed.

Step 8

5.6 Calculate the average rate of the reaction (in mol·min$^{-1}$) with respect to zinc for experiment 2 if 1.5g of zinc is used.

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Answer

To find the average rate of the reaction, we first need to calculate the number of moles of zinc used. Given the molar mass of zinc is approximately 65 g/mol:

n(Zn)=1.5 g65 g/mol=0.023 moln(Zn) = \frac{1.5 \text{ g}}{65 \text{ g/mol}} = 0.023 \text{ mol}

The reaction time for experiment 2 is 12 minutes. Thus, the average rate can be calculated as:

Rate=n(Zn)Δt=0.023 mol12 min0.00192 mol\cdotpmin1\text{Rate} = \frac{n(Zn)}{\Delta t} = \frac{0.023 \text{ mol}}{12 \text{ min}} \approx 0.00192 \text{ mol·min}^{-1}

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