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The flow diagram below shows the steps used to prepare fertilisers X and Y - NSC Physical Sciences - Question 10 - 2018 - Paper 2

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The flow diagram below shows the steps used to prepare fertilisers X and Y. Labels I and II represent types of chemical reactions and P is a compound. P + H₂(g) → ... show full transcript

Worked Solution & Example Answer:The flow diagram below shows the steps used to prepare fertilisers X and Y - NSC Physical Sciences - Question 10 - 2018 - Paper 2

Step 1

10.1.1 Write down the NAME of the reaction labelled I

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Answer

The reaction labelled I is known as the 'Catalytic oxidation of ammonia'.

Step 2

10.1.2 Write down the NAME of the reaction labelled II

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Answer

The reaction labelled II is referred to as 'Neutralisation/acid-base reaction'.

Step 3

10.2.1 Write down the NAME or FORMULA of Compound P

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Answer

Compound P is Nitric acid with the formula HNO₃.

Step 4

10.2.2 The brown gas

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Answer

The brown gas produced in the reaction is Nitrogen dioxide (NO₂).

Step 5

10.2.3 Liquid C

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Answer

Liquid C is Nitric acid (HNO₃).

Step 6

10.3.1 Write down a balanced equation for the preparation of fertiliser X

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Answer

The balanced equation for the preparation of fertiliser X is:

2NH3+H2SO4(NH4)2SO42NH₃ + H₂SO₄ → (NH₄)₂SO₄

Step 7

10.3.2 Write down a balanced equation for Reaction I

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Answer

The balanced equation for Reaction I is:

4NH3+5O24NO+6H2O4NH₃ + 5O₂ → 4NO + 6H₂O

Step 8

10.4 Fertiliser Y is ammonium nitrate. Calculate the mass percentage of nitrogen in fertiliser Y.

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Answer

Fertiliser Y is ammonium nitrate (NH₄NO₃). To calculate the mass percentage of nitrogen:

  • Molar mass of NH₄NO₃:

    • N: 14 g/mol × 2 = 28 g/mol
    • H: 1 g/mol × 4 = 4 g/mol
    • O: 16 g/mol × 3 = 48 g/mol
    • Total: 28 + 4 + 48 = 80 g/mol
  • % N = (mass of N / molar mass of NH₄NO₃) × 100 = (28 / 80) × 100 = 35%.

Thus, the mass percentage of nitrogen in fertiliser Y is 35%.

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