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A roller-coaster car of mass 200 kg, with the engine switched off, travels along track ABC which has a rough surface, as shown in the diagram below - NSC Physical Sciences - Question 5 - 2020 - Paper 1

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A roller-coaster car of mass 200 kg, with the engine switched off, travels along track ABC which has a rough surface, as shown in the diagram below. At point A, whic... show full transcript

Worked Solution & Example Answer:A roller-coaster car of mass 200 kg, with the engine switched off, travels along track ABC which has a rough surface, as shown in the diagram below - NSC Physical Sciences - Question 5 - 2020 - Paper 1

Step 1

5.1 Define the term non-conservative force.

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Answer

A non-conservative force is a force for which the work done on an object depends on the path taken. Unlike conservative forces, such as gravity, which are path-independent, non-conservative forces (like friction) do not store mechanical energy.

Step 2

5.2 Calculate the change in the kinetic energy of the car after it has travelled from point A to point B.

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The change in kinetic energy (ΔK) can be calculated using the formula:

egin{align*} ext{Initial Kinetic Energy (K}_A ext{)} &= rac{1}{2} m v_A^2 \\ ext{Final Kinetic Energy (K}_B ext{)} &= rac{1}{2} m v_B^2 \\ ext{ΔK} &= K_B - K_A egin{align*}

Substituting the given values:

K_A = rac{1}{2} imes 200 imes (4)^2 = 1600 ext{ J} \\ K_B = rac{1}{2} imes 200 imes (2)^2 = 400 ext{ J}

Calculating the change:

ΔK=4001600=1200extJΔK = 400 - 1600 = -1200 ext{ J}

Step 3

5.3 Use energy principles to calculate the height h.

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Answer

Applying the principle of conservation of energy, the total mechanical energy at point A equals the total mechanical energy at point B plus the work done against friction:

mg(h+10)+KAW=mg(h)+KBmg(h + 10) + K_A - W = mg(h) + K_B

Substituting the known values, where m = 200 kg:

200imes9.8imes10+16003.40imes103=200imes9.8imesh+400200 imes 9.8 imes 10 + 1600 - 3.40 imes 10^3 = 200 imes 9.8 imes h + 400

This simplifies to:

19600+16003400=1960h+40019600 + 1600 - 3400 = 1960h + 400

Further simplifying gives:

19600+16003400400=1960h19600 + 1600 - 3400 - 400 = 1960h =196003400400=1960h= 19600 - 3400 - 400 = 1960 h

The final rearrangement yields:

h = rac{19600 - 3400 - 400}{1960} \\ = rac{ 17800}{1960} \\ ≈ 9.08 ext{ m}

Step 4

5.4 Calculate the power delivered by the engine to move the car from point B to point C.

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Answer

Power can be calculated using the formula:

P = rac{W}{t}

Where W is the work done. The total work done against friction during the movement from point B to point C can be calculated using:

W=FimesdW = F imes d

The distance (d) the car travels from B to C is:

d=vimest=2imes5=10extmd = v imes t = 2 imes 5 = 10 ext{ m}

The work done against friction:

Wfriction=50imes10=500extJW_{friction} = 50 imes 10 = 500 ext{ J}

Thus, the total work done by the engine, considering the change in gravitational potential energy moving up (ΔPE), is:

W=Wfriction+ΔPE=500+(200)(9.8)(22h)W = W_{friction} + ΔPE = 500 + (200)(9.8)(22 - h)

Calculating ΔPE gives:

ΔPE=200imes9.8imes(2210)ΔPE = 200 imes 9.8 imes (22 - 10)

Calculating the total:

W=500+(200)(9.8)(12)=500+23520=24020extJW = 500 + (200)(9.8)(12) \\ = 500 + 23520 \\ = 24020 ext{ J}

Finally, substituting into the power formula:

P = rac{24020}{5} = 4804 ext{ W}

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