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The graph below represents function $k$ defined by $k(x) = x^2 + 3x$ - NSC Technical Mathematics - Question 2 - 2021 - Paper 1

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The graph below represents function $k$ defined by $k(x) = x^2 + 3x$. Describe the nature of the real roots of $k$. 2.2 Show that the roots of $x^2 + px - 2p^2 = 0... show full transcript

Worked Solution & Example Answer:The graph below represents function $k$ defined by $k(x) = x^2 + 3x$ - NSC Technical Mathematics - Question 2 - 2021 - Paper 1

Step 1

Describe the nature of the real roots of $k$.

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Answer

To determine the nature of the real roots, we can analyze the graph of the function k(x)k(x). Since the graph is a parabola that opens upwards and intersects the x-axis at two points (indicating two real roots), we conclude that the roots are real and rational. This is supported by the fact that the x-coordinates of the intersections are whole numbers, specifically x=3x = -3 and x=0x = 0.

Step 2

Show that the roots of $x^2 + px - 2p^2 = 0$ are rational for $p$ real numbers.

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Answer

To show that the roots are rational, we can calculate the discriminant of the quadratic equation. The discriminant riangle riangle is given by:

riangle=b24ac riangle = b^2 - 4ac

For our equation, where a=1a = 1, b=pb = p, and c=2p2c = -2p^2, we substitute:

riangle=(p)24(1)(2p2) riangle = (p)^2 - 4(1)(-2p^2)

This simplifies to:

riangle=p2+8p2=9p2 riangle = p^2 + 8p^2 = 9p^2

The discriminant riangle=9p2 riangle = 9p^2 is a perfect square, as 9p2=(3p)29p^2 = (3p)^2. Since the discriminant is a perfect square, we conclude that the roots of the quadratic equation are rational for all real numbers pp.

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