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This diagram represents a p-n junction diode - NSC Technical Sciences - Question 7 - 2020 - Paper 1

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This diagram represents a p-n junction diode. 7.1 Name the type of material indicated by A and B. 7.1.2 Draw the symbol for this p-n junction diode. 7.1.3 How man... show full transcript

Worked Solution & Example Answer:This diagram represents a p-n junction diode - NSC Technical Sciences - Question 7 - 2020 - Paper 1

Step 1

Name the type of material indicated by A and B.

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Answer

Material A is a p-type semiconductor, while Material B is an n-type semiconductor. The p-type material has an abundance of holes (positive charge carriers), and the n-type material has an abundance of free electrons (negative charge carriers).

Step 2

Draw the symbol for this p-n junction diode.

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Answer

The symbol for a p-n junction diode consists of a triangle pointing towards a line, with the triangle representing the p-type material and the line representing the n-type material.

  /|
 / |
---|

In this representation, the arrow indicates the direction of conventional current flow, from p-type to n-type.

Step 3

How many valence electrons does an intrinsic semiconductor have?

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An intrinsic semiconductor, such as silicon or germanium, has four valence electrons. This allows for the formation of covalent bonds within the crystal structure.

Step 4

Define a capacitor.

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A capacitor is an electrical component that stores electrical energy in an electric field. It consists of two conductive plates separated by an insulating material, known as a dielectric. When a voltage is applied across the plates, an electric field is created, allowing the capacitor to store charge.

Step 5

State the relationship between the capacitance and the charge on the plates.

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Answer

The relationship between the capacitance (C) and the charge (Q) stored on the plates is given by the formula:

Q=CimesVQ = C imes V

where VV is the voltage across the plates of the capacitor. This indicates that the charge is directly proportional to both the capacitance and the voltage.

Step 6

State TWO changes that you can make to the capacitor to decrease the capacitance.

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  1. Decrease the surface area of the conductive plates: Reducing the area of the plates will decrease the amount of charge that can be stored, thus decreasing the capacitance.

  2. Increase the distance between the plates: By separating the plates further apart, the capacitance will decrease due to a reduction in the electric field strength between them.

Step 7

A lamp filament has a resistance of 60 Ω and draws a current of 2 A when connected across a 120 V supply. Calculate the cost of electricity consumed in two hours, if the tariff is R1.75 per kWh.

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Answer

First, we calculate the power consumed by the lamp using the formula:

P=I2imesRP = I^2 imes R

Where:

  • I=2extAI = 2 ext{ A}
  • R=60extΩR = 60 ext{ Ω}

Thus,

P=(2extA)2imes60extΩ=4imes60=240extW=0.24extkWP = (2 ext{ A})^2 imes 60 ext{ Ω} = 4 imes 60 = 240 ext{ W} = 0.24 ext{ kW}

Next, we calculate the energy consumed in two hours:

extEnergy=Pimest=0.24extkWimes2exth=0.48extkWh ext{Energy} = P imes t = 0.24 ext{ kW} imes 2 ext{ h} = 0.48 ext{ kW·h}

Finally, the cost of the electricity consumed is:

extCost=extEnergyimesexttariff=0.48extkWhimesR1.75/extkWh=R0.84 ext{Cost} = ext{Energy} imes ext{tariff} = 0.48 ext{ kW·h} imes R1.75/ ext{kW·h} = R0.84

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