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6.1 A light ray strikes a reflective plane surface at an angle of 58° with the surface - NSC Technical Sciences - Question 6 - 2023 - Paper 1

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6.1 A light ray strikes a reflective plane surface at an angle of 58° with the surface. 6.1.1 Define the term reflection. 6.1.2 Label the following: Light ray OB A... show full transcript

Worked Solution & Example Answer:6.1 A light ray strikes a reflective plane surface at an angle of 58° with the surface - NSC Technical Sciences - Question 6 - 2023 - Paper 1

Step 1

Define the term reflection.

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Answer

Reflection is the change in direction of a wave upon striking the interface between two materials, often described as the bouncing back of a wave when it encounters a boundary.

Step 2

Label the following: Light ray OB.

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Answer

The light ray can be labeled as OB, which is the incident ray striking the surface at an angle.

Step 3

Label the following: Angle 1.

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Answer

Angle 1 is defined as the angle of incidence, which is the angle formed between the incident ray (OB) and the normal at the surface.

Step 4

Label the following: Angle 2.

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Answer

Angle 2 is identified as the angle of reflection, which is formed between the reflected ray and the normal.

Step 5

State the relationship between angle 1 and angle 2.

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Answer

According to the law of reflection, angle 1 (angle of incidence) is equal to angle 2 (angle of reflection): extAngle1=extAngle2 ext{Angle 1} = ext{Angle 2}

Step 6

Name the phenomenon observed in the diagram.

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Answer

The phenomenon observed in the diagram is known as refraction.

Step 7

State TWO applications of the phenomenon in QUESTION 6.2.1.

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Answer

  1. Optical fibers in telecommunications to transmit data over long distances.
  2. Automotive rain sensors that detect moisture on windshields.

Step 8

Write down TWO conditions for the phenomenon in QUESTION 6.2.1.

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Answer

  1. The light must be traveling from a denser medium to a less dense medium (e.g., from glass to air).
  2. The angle of incidence must be greater than the critical angle.

Step 9

Name the type of lens used in the diagram.

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Answer

The lens used in the diagram is a convex lens.

Step 10

State TWO properties of the image formed by the lens in QUESTION 6.3.1.

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Answer

  1. The image is real and inverted.
  2. The image is enlarged as the object is placed between F and 2F.

Step 11

Give TWO uses of the lens in QUESTION 6.3.1.

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Answer

  1. Used in magnifying glasses to enlarge images for better visibility.
  2. Used in optical microscopes for viewing small specimens.

Step 12

Give a reason why NO IMAGE is formed when the object is placed at F.

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Answer

No image is formed when the object is placed at F because the rays passing through the optical center are parallel and will not converge or diverge to form an image.

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