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QUESTION 9 (Start on a new page.) A total magnetic flux of 9 Wb passes through a rectangular coil with a length of 150 mm and a width of 90 mm - NSC Technical Sciences - Question 9 - 2021 - Paper 1

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Question 9

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QUESTION 9 (Start on a new page.) A total magnetic flux of 9 Wb passes through a rectangular coil with a length of 150 mm and a width of 90 mm. 9.1 Define magnetic... show full transcript

Worked Solution & Example Answer:QUESTION 9 (Start on a new page.) A total magnetic flux of 9 Wb passes through a rectangular coil with a length of 150 mm and a width of 90 mm - NSC Technical Sciences - Question 9 - 2021 - Paper 1

Step 1

Define magnetic flux density.

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Answer

Magnetic flux density, denoted as B, is defined as the number of magnetic field lines that are perpendicular to a given surface. It can also be described as the number of field lines per unit area, which is expressed mathematically as:

B=ΦAB = \frac{\Phi}{A}

where,

  • Φ\Phi is the magnetic flux in Weber (Wb) and
  • AA is the area in square meters (m²).

Step 2

Calculate the magnetic flux density that passes through this rectangular coil with length 150 mm and width 90 mm.

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Answer

To calculate the magnetic flux density, we first need to determine the area of the rectangular coil:

  1. Convert the dimensions from mm to m:

    • Length = 150 mm = 0.150 m
    • Width = 90 mm = 0.090 m
  2. Calculate the area (A): A=l×b=0.150×0.090=0.0135 m2A = l \times b = 0.150 \times 0.090 = 0.0135 \ \, m^2

  3. Given the total magnetic flux (Φ\Phi) is 9 Wb, we use the formula to find B: B=ΦA=90.0135B = \frac{\Phi}{A} = \frac{9}{0.0135} B666.67T B \approx 666.67 \, T \

Therefore, the magnetic flux density that passes through the rectangular coil is approximately 666.67 Tesla.

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