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Die selnotasie Zn(s)|Zn²⁺ (aq)|Cu²⁺ (aq)|Cu(s) verteenwoordig 'n galvaniese sel wat onder standaardtoestande funksioneer - NSC Technical Sciences - Question 6 - 2020 - Paper 2

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Die-selnotasie-Zn(s)|Zn²⁺-(aq)|Cu²⁺-(aq)|Cu(s)-verteenwoordig-'n-galvaniese-sel-wat-onder-standaardtoestande-funksioneer-NSC Technical Sciences-Question 6-2020-Paper 2.png

Die selnotasie Zn(s)|Zn²⁺ (aq)|Cu²⁺ (aq)|Cu(s) verteenwoordig 'n galvaniese sel wat onder standaardtoestande funksioneer. 6.1.1 Definieer die term galvaniese sel. ... show full transcript

Worked Solution & Example Answer:Die selnotasie Zn(s)|Zn²⁺ (aq)|Cu²⁺ (aq)|Cu(s) verteenwoordig 'n galvaniese sel wat onder standaardtoestande funksioneer - NSC Technical Sciences - Question 6 - 2020 - Paper 2

Step 1

Definieer die term galvaniese sel.

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Answer

A galvanic cell is an electrochemical cell that converts chemical energy into electrical energy through spontaneous redox reactions.

Step 2

Teken 'n benoemde diagram om die Zn-Cu-sel voor te stel. Toon die vloeiing van die elektrone in die ekstreme stroombaan.

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Answer

The diagram should include:

  • Anode on the left (Zn electrode).
  • Cathode on the right (Cu electrode).
  • Salt bridge connecting both half-cells.
  • Flow of electrons from Zn (anode) to Cu (cathode), indicated with arrows.

Step 3

Skryf TWEE standaardpotensiale neer waaronder die Zn-Cu-sel funksioneer.

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Answer

E°(Zn²⁺/Zn) = -0.76 V E°(Cu²⁺/Cu) = +0.34 V

Step 4

Na watter halfsel migreer (beweeg) die anione in die soutbrug?

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Answer

The anions migrate towards the Zn half-cell.

Step 5

Verduidelik die antwoord op VRAAG 6.1.4.

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Anions move towards the zinc half-cell because zinc is oxidizing and producing Zn²⁺ ions, thus creating a shortage of negative charge that the anions need to balance.

Step 6

Die anode in die Zn-Cu-sel word deur 'n onbekende elektroode, X, verteenwoordig. Die voltmeter gee 'n lesing van 2,00 V.

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Answer

This indicates that the overall cell potential is positive, suggesting that the oxidation reaction at anode X is favorable.

Step 7

Skryf 'n vergelyking neer wat X gebruik in die berekening.

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Answer

The cell potential can be calculated using: E°cell=E°cathodeE°anodeE°_{cell} = E°_{cathode} - E°_{anode} For cell X: 2.00 V = (+0.34 V) - E°(X)

Step 8

Skryf die elektrode se naam in afkorting.

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Answer

X = Aluminium/A⁺/negative electrode.

Step 9

Verduidelik die antwoord op VRAAG 6.2.3.

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Answer

The explanation should involve the role of electrode X in the electrochemical reactions that occur in relation to zinc oxidation and copper reduction.

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