Photo AI

Last Updated Sep 13, 2025

Dilution of solutions Simplified Revision Notes

Revision notes with simplified explanations to understand Dilution of solutions quickly and effectively.

user avatar
user avatar
user avatar
user avatar
user avatar

269+ students studying

Dilution of solutions

1. What is Dilution?

  • Dilution is the process of reducing the concentration of a solution by adding distilled water.
  • The amount of solute remains the same, but the volume of solution increases, decreasing the concentration.

2. Dilution Formula

C1V1=C2V2C_1V_1 = C_2V_2

where:

  • C1=C₁ = initial (concentrated) solution concentration (moldm3)(mol·dm⁻³)
  • V1=V₁ = volume of the initial solution (dm3)(dm³)
  • C2=C₂ = final (diluted) solution concentration (moldm3)(mol·dm⁻³)
  • V2=V₂ = final volume after dilution (dm3)(dm³)

3. How to Perform a Dilution

  1. Measure a known volume of the concentrated solution (V1).(V₁).
  2. Add distilled water to reach the desired final volume (V2).(V₂).
  3. Mix thoroughly to ensure even dilution.
infoNote

4. Worked Example

Problem:

A 0.200.20 moldm3mol·dm⁻³ solution is diluted by adding 250250 cm3cm³ of distilled water to 150150 cm3cm³ of the solution.

Calculate the final concentration of the diluted solution.

Solution:

Step 1: Identify known values

  • C1=C₁ = 0.200.20 moldm3mol·dm⁻³
  • V1=V₁ = 150150 cm3cm³ =0.15= 0.15 dm3dm³
  • V2=V₂ = 150150 cm3+250cm3cm³ + 250 cm³ =400cm3= 400 cm³ =0.4dm3= 0.4 dm³
  • C2=C₂ = ?

Step 2: Apply the dilution formula

C2=C1V1V2C_2 = \frac{C_1V_1}{V_2}

C2=(0.20)(0.15)0.4C_2 = \frac{(0.20)(0.15)}{0.4}

C2=0.075moldm3C_2 = 0.075 mol·dm⁻³

Thus, the final concentration of the diluted solution is 0.0750.075 moldm3mol·dm⁻³.

5. Key Points to Remember

Dilution does NOT change the number of moles of solute, only the concentration.

✅ The greater the volume of water added, the lower the final concentration.

✅ Always convert cm3cm³ to dm3dm³ (10001000 cm3cm³ == 11 dm3dm³) when using the formula.

Books

Only available for registered users.

Sign up now to view the full note, or log in if you already have an account!

500K+ Students Use These Powerful Tools to Master Dilution of solutions

Enhance your understanding with flashcards, quizzes, and exams—designed to help you grasp key concepts, reinforce learning, and master any topic with confidence!

920 flashcards

Flashcards on Dilution of solutions

Revise key concepts with interactive flashcards.

Try Physical Sciences Flashcards

103 quizzes

Quizzes on Dilution of solutions

Test your knowledge with fun and engaging quizzes.

Try Physical Sciences Quizzes

73 questions

Exam questions on Dilution of solutions

Boost your confidence with real exam questions.

Try Physical Sciences Questions

104 exams created

Exam Builder on Dilution of solutions

Create custom exams across topics for better practice!

Try Physical Sciences exam builder

76 papers

Past Papers on Dilution of solutions

Practice past papers to reinforce exam experience.

Try Physical Sciences Past Papers

Other Revision Notes related to Dilution of solutions you should explore

Discover More Revision Notes Related to Dilution of solutions to Deepen Your Understanding and Improve Your Mastery

96%

114 rated

Acids and Bases

Properties of acids and bases

user avatar
user avatar
user avatar
user avatar
user avatar

225+ studying

189KViews

96%

114 rated

Acids and Bases

Common acids

user avatar
user avatar
user avatar
user avatar
user avatar

233+ studying

180KViews

96%

114 rated

Acids and Bases

Common bases

user avatar
user avatar
user avatar
user avatar
user avatar

239+ studying

181KViews

96%

114 rated

Acids and Bases

Mono- and polyprotic acids

user avatar
user avatar
user avatar
user avatar
user avatar

453+ studying

180KViews
Load more notes

Join 500,000+ NSC students using SimpleStudy...

Join Thousands of NSC Students Using SimpleStudy to Learn Smarter, Stay Organized, and Boost Their Grades with Confidence!

97% of Students

Report Improved Results

98% of Students

Recommend to friends

500,000+

Students Supported

50 Million+

Questions answered