Photo AI

Last Updated Sep 27, 2025

- Determination of the Relative Molecular Mass of a Volatile Liquid Simplified Revision Notes

Revision notes with simplified explanations to understand - Determination of the Relative Molecular Mass of a Volatile Liquid quickly and effectively.

user avatar
user avatar
user avatar
user avatar
user avatar

229+ students studying

3.1 - Determination of the Relative Molecular Mass of a Volatile Liquid

infoNote

Experiment Summary

This experiment uses the ideal gas equation PV=nRTPV = nRT to estimate the relative molecular mass (MrM_r) of a volatile liquid. The liquid is vaporised in a container at a known temperature, volume, and pressure, allowing the number of moles of vapour to be calculated.

By measuring the mass of the vapour, the relative molecular mass is determined.

Materials and Apparatus Required

Chemicals

  • Volatile liquid (e.g., propanone)
  • Water

Apparatus

  • 250 cm³ conical flask
  • 600 cm³ beaker
  • Aluminium foil
  • Clamp
  • Rubber band
  • Bunsen burner or hotplate
  • Tripod and gauze
  • Thermometer
  • Barometer
  • Electronic balance
  • 100 cm³ graduated cylinder
  • Pin
  • Dropping pipette

Safety Precautions

  • Wear safety glasses at all times.
  • Propanone is highly flammable. Ensure that the flask is far from open flames when adding the liquid.
  • Use a well-ventilated area to avoid inhaling propanone vapours.
  • Handle hot water and glassware with care to avoid burns.

Method

  1. Two-thirds fill a beaker with water and heat it to approximately 95°C using a Bunsen burner or hotplate.
  2. Record the mass of the dry conical flask, aluminium foil cap, and rubber band.
  3. Use a pipette to add 3–4 cm³ of propanone to the flask.
  4. Secure the flask with the foil cap and rubber band, then poke a small hole in the foil with a pin.
  5. Immerse the flask in the hot water bath, ensuring no vapour escapes except through the pinhole.
  6. The liquid will vaporise, and once it appears fully vaporised, remove the flask from the water.
  7. Measure the temperature of the water, which represents the temperature of the vapour.
  8. Let the flask cool, then measure its mass again. The difference in mass gives the mass of the vapour.
  9. Fill the flask with water, then transfer the water to a graduated cylinder to find the flask's volume.
  10. Use a barometer to record the atmospheric pressure.
  11. Calculate the relative molecular mass (MrM_r) of the volatile liquid using the ideal gas equation.

Results

MeasurementValue
Mass of flask, cap, and rubber bandg
Mass of flask, cap, rubber band, and vaporg
Mass of vaporg
Atmospheric pressuremmHg/Pa
Temperature of boiling water°C/K
Volume of flaskcm³/m³

Sample Calculation

Ideal Gas Equation:

PV=nRTPV = nRT

Calculate the number of moles of vapour (n):

n=PVRTn = \frac{PV}{RT}

Relative Molecular Mass:

Mr=mnMr = \frac{m}{n}

Example Questions with Answers

infoNote

Q1: Why is it necessary for the liquid to be volatile?

The liquid must easily vaporise at the temperature used in the experiment so that the ideal gas law can be applied accurately.

This ensures the vapour behaves similarly to an ideal gas.

infoNote

Q2: What other method could be used to determine the relative molecular mass?

Mass spectrometry can provide highly accurate measurements of molecular masses.

infoNote

Q3: Which measurement is most likely to introduce inaccuracy and why?

Volume measurement is prone to error because real gases deviate from ideal behaviour, particularly under conditions of high pressure or low temperature.

infoNote

Q4: How would a small drop of water in the flask affect the results?

The drop of water would vaporise and increase the volume of the gas, leading to an inaccurately high volume reading and a smaller calculated MrM_r.

infoNote

Q5: How would you calculate the density of the vapour at the boiling water temperature?

Use the formula:

Density=massvolume\text{Density} = \frac{\text{mass}}{\text{volume}}

For example, using sample data from the experiment:

Density=0.52g284cm3=0.0018g/cm3\text{Density} = \frac{0.52 \, \text{g}}{284 \, \text{cm}³} = 0.0018 \, \text{g/cm}³
Books

Only available for registered users.

Sign up now to view the full note, or log in if you already have an account!

500K+ Students Use These Powerful Tools to Master - Determination of the Relative Molecular Mass of a Volatile Liquid

Enhance your understanding with flashcards, quizzes, and exams—designed to help you grasp key concepts, reinforce learning, and master any topic with confidence!

20 flashcards

Flashcards on - Determination of the Relative Molecular Mass of a Volatile Liquid

Revise key concepts with interactive flashcards.

Try Chemistry Flashcards

2 quizzes

Quizzes on - Determination of the Relative Molecular Mass of a Volatile Liquid

Test your knowledge with fun and engaging quizzes.

Try Chemistry Quizzes

29 questions

Exam questions on - Determination of the Relative Molecular Mass of a Volatile Liquid

Boost your confidence with real exam questions.

Try Chemistry Questions

27 exams created

Exam Builder on - Determination of the Relative Molecular Mass of a Volatile Liquid

Create custom exams across topics for better practice!

Try Chemistry exam builder

115 papers

Past Papers on - Determination of the Relative Molecular Mass of a Volatile Liquid

Practice past papers to reinforce exam experience.

Try Chemistry Past Papers

Other Revision Notes related to - Determination of the Relative Molecular Mass of a Volatile Liquid you should explore

Discover More Revision Notes Related to - Determination of the Relative Molecular Mass of a Volatile Liquid to Deepen Your Understanding and Improve Your Mastery

96%

114 rated

Stoichiometry, Formulas and Equations

- Determination of the Relative Molecular Mass of a Volatile Liquid

user avatar
user avatar
user avatar
user avatar
user avatar

433+ studying

184KViews
Load more notes

Join 500,000+ Leaving Cert students using SimpleStudy...

Join Thousands of Leaving Cert Students Using SimpleStudy to Learn Smarter, Stay Organized, and Boost Their Grades with Confidence!

97% of Students

Report Improved Results

98% of Students

Recommend to friends

500,000+

Students Supported

50 Million+

Questions answered